Question

in the instant of fig. 11-41, two particles move in an xy plane. particle p1 has mass 6.5 kg and speed v1 2.2 m/s, and it is at dis- tance d1 1.5 m from point o. particle p2 has mass 3.1 kg and speed v2 3.6 m/s, and it is at distance d2 2.8 m from point o. what are the (a) magnitude and (b) direction of the

Answer 1

To find the magnitude and direction of the angular momentum of the particle about the origin, we can use the cross product between the position and velocity vectors and multiply it by the mass of the particle.

Step-by-step explanation:

To find the magnitude of the angular momentum of the particle about the origin, we can multiply the angular velocity (which is the cross product of the position and velocity vectors) by the mass of the particle. Using the given position and velocity vectors, we can calculate the angular momentum:

L = r x p = r×p×sin(theta)

where r is the position vector and p is the momentum vector. To find the direction of the angular momentum, we can use the right-hand rule, which states that if your fingers point from r to p, then your thumb will point in the direction of the angular momentum vector.

Answer 2

To solve this problem, we can use the concept of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision. By plugging in the given values, we can calculate the final velocities of the particles.

Step-by-step explanation:

To solve this problem, we can use the concept of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision.

(m1 * v1)+(m2 * v2) = (m1 * v1') + (m2 * v2')

Where m1 and m2 are the masses of the particles, v1 and v2 are their initial velocities, and v1' and v2' are their final velocities.

By plugging in the given values, we can calculate the final velocities of the particles.

After calculating the final velocities, we can find the magnitude and direction of the velocities using trigonometry.