Question

Given P(A) = 0.44, P(B) 0.6 and P(An B) = 0.394, find the value of

P(AUB), rounding to the nearest thousandth, if necessary.

Answer 1

Given:

`P(A)=0.44,P(B)=0.6,P(A\cap B)=0.394`.

To find:

The value of
`P(A\cup B)`, rounding to the nearest thousandth.

Solution:

We know that,

`P(A\cup B)=P(A)+P(B)-P(A\cap B)`

On substituting
`P(A)=0.44,P(B)=0.6,P(A\cap B)=0.394`, we get

`P(A\cup B)=0.44+0.6-0.394`

`P(A\cup B)=0.646`

Therefore, the value of
`P(A\cup B)` is 0.646.