Question

How many moles of aluminum oxide will be produced from 0.50 mol of oxygen?

4 Al + 3 O2→ 2 Al2O3

Answer 1

`\boxed {\boxed {\sf \frac {1}{3} \ mol \ Al_2O_3 \approx 0.34 \ mol \ Al_2O_3}}`

Step-by-step explanation:

We will use stoichiometry to solve this problem. The reaction given has a formula of

`4Al+3O_2 \rightarrow 2Al_2O_3`

The coefficients tell us the number of moles necessary for the reaction.

The reaction requires 3 moles of oxygen to produce 2 moles of aluminum oxide. We can make a ratio.

`\frac {3 \ mol \ O_2}{ 2\ mol \ Al_2O_3}}`

Since we are doing the reaction with 0.5 moles of oxygen, we multiply the ratio by that number.

`0.5 \ mol \ O_2 *\frac {3 \ mol \ O_2}{ 2 \ mol \ Al_2O_3}}`

Flip the ratio so the moles of oxygen cancel each other out.

`0.5 \ mol \ O_2 *\frac {2 \ mol \ Al_2O_3}{ 3 \ mol \ O_2}}`

`0.5 *\frac {2 \ mol \ Al_2O_3}{ 3 }`

`\frac {1 \ mol \ Al_2O_3}{ 3 }`

`\frac {1}{3} \ mol \ Al_2O_3 = 0.33333 \ mol \ Al_2O_3 \approx 0.34 \ mol \ Al_2O_3`

0.5 moles of oxygen produces 1/3 or approximately 0.34 moles of aluminum oxide.