Question

G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =

Answer 1

Given:

The two functions are:

`g(b)=5b-9`

`h(b)=(b-1)^2`

To find:

The value of
`(h\circ g)(-6)`.

Solution:

We have,

`g(b)=5b-9`

`h(b)=(b-1)^2`

We know that,

`(h\circ g)(b)=h(g(b))`

`(h\circ g)(b)=h(5b-9)`

`(h\circ g)(b)=[(5b-9)-1]^2`

`(h\circ g)(b)=[5b-10]^2`

Putting
`b=-6`, we get

`(h\circ g)(-6)=[5(-6)-10]^2`

`(h\circ g)(-6)=[-39-10]^2`

`(h\circ g)(-6)=[-49]^2`

`(h\circ g)(-6)=2401`

Therefore, the value of
`(h\circ g)(-6)` is 2401.