Question

1. f(x)=14(x-3)+1. g(x)=7(x+2)+1

2. f(x)=6(x+2)-3. g(x)=8(x-3)+6
3. f(x)=3(x-1)+²/3. g(x)=3(3-x)-2/3
4. f(x)=-1/3(x+2)-4. g(x)=¹/3(-x-2)+6
5. f(x)=4/3(x-2/3)+¹/3. g(x)=2/3 (2²/3 -x)

State the transformations that occur between f(x) and g(x). I would greatly appreciate if someone could help me with these! Thank you

Answer 1

Comparing the functions, from the tables, it is found that (f - g)(x) is positive in the interval (–∞, 9) .

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For the subtraction function, we simply subtract both functions, thus:

It is positive if f is greater than g, that is: f(x) > g(x).

It is a linear function, so one function is greater before the equality, one after.

They are equal at x = 9.

If x < 9, f(x) > g(x), and thus, (f - g)(x) is positive, which means that the desired interval is:

(–∞,

Explanation: