Question

What is the volume, in L, of 2.50 moles of oxygen gas measured at 25.0oC and a pressure of 104.5 kPa?

Answer 1

58.53 L

Step-by-step explanation:

Ideal gas equation is

PV = nRT

P - the pressure of the gas = 104.5 KPa

V- the volume occupied by the gas

n - the number of moles of gas =2.50

R - the universal gas constant, usually given as 0.0821 atm.L/(mol K)

T - the absolute temperature of the gas.= 298K

`V =(nRT)/(P)`

Now substituting vales we get

`V = (2.5*0.0821*298)/(104.5*1000)`

V = 58.53 L