Question

How do you solve 2cos2^x = 1 ?

Answer 1

Explanation:

Solve for x:

2 cos* (2) =

Divide both sides by 2:

cost (2) =

Take the logarithm base cos(2) of both sides:

Answer:

2inn

X=

iT+ log(-cos(2))

log(2)

i7+ log(-cos(2))

for NE Z