Question

1. What is the solution of n^2-49=0?

a. -7
b.7
c.≠7
d. no solution

2. What is the solution of x^2+64=0?
a.-5
b.8
c.≠8
d.no solution

3. What is the length of a square with an area of 144x^2
a.12
b.12x
c.≠4in
d.no solution

4. What is the value of b in the triangle?
a.-4in
b.4in
c.≠4in
d.no solution

5. What is the value of z so that -9 and 9 are both solutions of x^2+z=103

Answer 1

1. a

2. b

3. b

4. b

5. 22

Step-by-step explanation:

1.

n²-49=0

n=√49

n=7

2.

x²+64=0

x=√64

x=8

3.

if A=144x²

l = √A

l = √(144x²)

l = 12x

4.

b = (24×2)/3b

b = 48/3b

b = 16/b

b² = 16

b = √16

b = 4 in (-4 is correct in algebra but there's no negative lengths in geometric shapes)

5.

x²+z = 103

x² = 103-z

x = √(103-z)

for x = -9 and 9 (103-z) must equal 81

z = 103 - 81 = 22

x = √(103-22)

x = √81

x = -9 , 9