Question

Glucose (C6H12O6) is used as a source of energy by the human body. The overall unbalanced chemical equation is:

C6H12O6 + O2 → CO2 + H2O

Calculate the number of grams of oxygen gas needed to oxidize 12.5 g of glucose to carbon dioxide and water. (Remember that oxygen gas is a diatomic gas.)

Answer 1

13.3 grams O2

Step-by-step explanation:

Balance the equation first:

C6H12O6 + 6O2 → 6CO2 + 6H2O

Convert grams of glucose to moles:

12.5 g * (1 mol C6H12O6/180.155g) = 0.694 mol C6H12O6

Use ratio of oxygen gas to glucose to convert to moles of oxygen gas:

0.694 mol C6H12O6 * (6 mol O2/1 mol C6H12O6) = 0.416 mol O2

Convert moles of oxygen gas to grams:

0.416 mol O2 * (32.00g/1 mol O2) = 13.3 grams O2