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The midpoints of the sides of a triangle are given. find the vertices of the original triangle. explain your process and how you can check the answer

P (2, 1), Q (4, 5), R(7, 4)

please explain how to solve this

1 Answer

6 votes

Answer:

Explanation:

Step 1

1 of 5

Graph the three points and connect them to create the mid segments of the triangle:

Use midsegments of triangles in the coordinate plane.

Use the Triangle Midsegment Theorem to fi nd distances.

Using the Midsegment of a Triangle

A midsegment of a triangle is a segment that connects the

midpoints of two sides of the triangle. Every triangle has

three midsegments, which form the midsegment triangle.

The midsegments of △ABC at the right are MP —, MN —,

and NP —. The midsegment triangle is △MNP.

Using Midsegments in the Coordinate Plane

In △JKL, show that midsegment MN — is parallel to JL —

and that MN =

1

—2 JL.

SOLUTION

Step 1 Find the coordinates of M and N by fi nding

the midpoints of JK — and KL —.

M (—

−6 + (−2)

2

, —

1 + 5

2

) = M ( −8 —

2

, 6

2

) = M(−4, 3)

N (—

−2 + 2

2

, —

5 + (−1)

2

) = N ( 0

2

, 4

2

) = N(0, 2)

Step 2 Find and compare the slopes of MN — and JL —.

slope of MN —= —

2 − 3

0 − (−4) = −

1

4

slope of JL — = —

−1 − 1

2 − (−6) = −

2

8

= −

1

4

Because the slopes are the same, MN — is parallel to JL —.

Step 3 Find and compare the lengths of MN — and JL —.

MN = √——

[0 − (−4)]2 + (2 − 3)2 = √—

16 + 1 = √—

17

JL = √———

[2 − (−6)]2 + (−1 − 1)2 = √—

64 + 4 = √—

68 = 2 √—

17

JL = √———

[2 − (−6)]2 + (−1 − 1)2 = √—

64 + 4 = √—

68 = 2 √—

17

Because √—

17 =

1

—2

(2 √—

17 ) , MN =

1

—2 JL.

Monitoring Progress onitoring Progress Help in English and Spanish at BigIdeasMath.com

Use the graph of △ABC.

1. In △ABC, show that midsegment DE — is parallel

to AC — and that DE =

1

—2 AC.

2. Find the coordinates of the endpoints of

midsegment EF —, which is opposite AB —. Show

that EF — is parallel to AB — and that EF =

1

—2 AB.

READING

In the fi gure for Example 1,

midsegment MN — can be

called “the midsegment

opposite JL —.”

midsegment of a triangle,

p. 330

Previous

midpoint

parallel

slope

coordinate proof

Core Vocabulary Core Vocabulary

A C

P

N

M

B

x

y

4

6

−2

−6 −4 −2

M

N

K(−2, 5)

J(−6, 1)

L(2, −1)

x

y

−4

−6

−2 2 4 6

D

E

C(5, 0)

B(−1, 4)

A(

User Marcus Kaseder
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