Question

The 'parseInt' method of the 'Integer' class throws a 'NumberFormatException' when it is passed a String argument that it cannot convert to an int. Given the String variable s (which has already been assigned a value), write the code needed to convert the value in s assigning the result to the integer variable i

Answer 1

To convert the value in the string variable s and assign the result to the integer variable i, you can use the parseInt method of the Integer class, as shown below:

try {

// Attempt to parse the string and convert it to an integer

int i = Integer.parseInt(s);

} catch (NumberFormatException e) {

// Catch the NumberFormatException if it is thrown

// and handle the error as needed

}

In this code, the parseInt method is used to attempt to convert the value in s to an integer. If the method is successful, the resulting integer value will be assigned to the variable i. If the method is unable to convert the value in s to an integer, it will throw a NumberFormatException, which is caught by the catch block and can be handled as needed.

It is important to note that this code assumes that the s variable has already been assigned a value. If the variable has not been assigned a value, or if the value is not a valid string representation of an integer, the parseInt method may throw a NumberFormatException and the code in the catch block will be executed.