Question

write the equation of the line in slope-int form that is perpendicular to y=-x - 18 and passes through (-6,11)

Answer 1

y = x + 17

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - x - 18 ← is in slope- intercept form

with slope m = - 1

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(-1)` = 1 , then

y = x + c ← is the partial equation of the perpendicular line

to find c substitute (- 6, 11 ) into the partial equation

11 = - 6 + c ⇒ c = 11 + 6 = 17

y = x + 17 ← equation of perpendicular line