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Find the sum for:

(3x^2+4x−1)+(−2x^2−3x+2)=

User Seriously
by
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1 Answer

4 votes

Answer:

x^2+x+1

Explanation:

(3x^2+4x−1)+(−2x^2−3x+2)

Combine like terms

3x^2-2x^2+4x-3x-1+2

x^2+x+1

User Nurzhan Nogerbek
by
3.4k points