Answer:
0.373248
Explanation:
P(A and B) = P(A) * P(B)
Let's say one person wearing a seat belt is event A, the second person wearing a seat belt is event B, and the third person wearing their seat belt is event C
P(A and B and C) = P((A and B) and C) = (P(A) * P(B)) *P(C) = P(A) * P(B) * P(C)
The probability of each is 0.72. Our answer is therefore 0.72 * 0.72 * 0.72, or 0.72³ = 0.373248