Question

Prove that the roots of the equation mx² + (m − 2)x − (m + 1) = 0 are real for all values of m

Answer 1

Below

Explanation:

For REAL numbers, the discriminant of the Quadratic Formula has to be a positive value (or zero)

b^2 - 4ac >= 0 where a = m b = m-2 c = -m-1

(m-2)^2 - 4(m)(-m-1) >=0

5m^2 +4 >= 0

5 m^2 +4 <===== will always be >= 0 for any value of 'm'

so all roots will be real