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Find all values of x for which the perimeter is at most 32​

Find all values of x for which the perimeter is at most 32​-example-1
User Glenacota
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1 Answer

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Answer:

0 < x ≤ 11

Explanation:

perimeter = (x - 6) + (x - 6) + x + x

⇒ perimeter = 4x - 12

If the perimeter is "at most 32" then

4x - 12 ≤ 32

⇒ 4x ≤ 44

⇒ x ≤ 11

Therefore, 0 < x ≤ 11

User Sandesh Kobal
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7.3k points