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In circle R with m ∠ Q R S = 134 m∠QRS=134 and Q R = 6 QR=6 units find area of sector QRS. Round to the nearest hundredth.

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Answer:

142.10 units²

Explanation:


A = (n)/(360^\circ)\pi r^2


A = (134^\circ)/(360^\circ)\pi * 6^2


A = (134^\circ)/(360^\circ)\pi * 6^2


A = 142.10~units^2

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