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Consider the function c(x) = (x + 5)(x - 2)².

1. What are the zeroes of c(x)?

2. What is the degree of c(x)?

User Rsanden
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1 Answer

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Explanation:

Set each binomial equal to 0, solve for x.


(x + 5) = 0


x = - 5


(x - 2) {}^(2) = 0


x - 2 = 0


x = 2

The zeroes are -5, and 2(with a multiplicity of 2)

We have a degree of 3.


(x + 5)(x {}^(2) - 4x + 4)

the first term in each binomail when using FOIL, become x^3 since that is the highest degree, 3 is the degree of c.

User Psoshmo
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