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A 2 kg bird falls from a 15 m high tree. How fast is the bird falling right before it hits the ground?

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v^2= v0^2 + 2a*dx
v - instantaneous velocity (velocity at the moment)
v0 - initial velocity
dx - total displacement
a - acceleration
We should find v from this formula

As the bird is falling from the tree, initially it doesn’t have any velocity, so v0=0

When the bird will hit the ground, its total displacement will be 15m, so dx = 0

The acceleration here is equal to the gravitational acceleration (g) = 9.8

So if we will plug in our values to this formula:
v^2=0+2*9.8*15=294
v=17.15 m/s (this answer depends on whether you take g=9.8 or g=10)


Btw, mass doesn’t affect the acceleration and the velocity
User IPSDSILVA
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