Question

Consider the function f(x) = (x²-x)(x + 5).

1. What are the zeroes of f(x)?

2. Write f(x) in standard polynomial form.

Answer 1

Explanation:

`( {x}^(2) - x)(x + 5)`

`x(x - 1)(x + 5)`

`x = 0`

`x - 1 = 0`

`x = 1`

`x + 5 = 0`

`x = - 5`

So our zeroes are 0,1, and -5

2.

`{x}^(3) + 4 {x}^(2) - 5x`