Answer:
The answer is 81.85%
Explanation:
Given;
The z score is used to determine by how many standard deviations the raw score is above or below the mean.
The z score is given by:
z = x - μ/σ
where,
- x = raw score
- μ = mean
- σ = standard deviation
For x = 88
z = 88 - 116/14
z = (-2)
For x = 130
z = 130 - 116/14
z = (1)
Thus,
P(88 < x < 130) = P(-2 < z < 1)
= P(z < 1) - P(z < -2)
= 0.8413 - 0.0228 = 81.85%
Thus, 81.85% of the population would be between 88 and 130.