Question

In horses, black color (B) dominates chestnut color (b). The trotting

gait (T) dominates the pacing gait (t). A cross is made between a
horse homozygous for black color and the pacing gait and a horse homo
zygous for chestnut color and the trotting gait. List the probable geno
type and phenotype resulting from such a cross. List the probable
phenotypes of offspring that could result if the offspring from the
original cross were crossed among themselves.

Answer 1

For the first one, there is only one genotype and phenotype. The genotype is BbTt with the horse showing the black color and having a trotting gait.

For the second cross, there are 9 different genotypes. They are:

BBTT, BBTt, BBtt, BbTT, BbTt, Bbtt, bbTT, bbTt, bbtt

Showing dominant for both traits: 4

Showing dominant for only color: 2

Showing dominant for only gait: 2

Showing recessive for both traits: 1

4/9 Both Dominant

2/9 Color Dominant Only

2/9 Gait Dominant Only

1/9 Both Recessive

Step-by-step explanation:

You have to use a dihybrid cross for both of the crosses because there are two different traits present.

Answer 2

First Cross:

Bt Bt

bT BbTt BbTt

bT BbTt BbTt

BbTt= Black colour, trotting gait

Second Cross:

BT Bt bT bt

BT BBTT BBTt BbTT BbTt

Bt BBTt BBtt BbTt Bbtt

bT BbTT BbTt bbTT bbTt

bt BbTt Bbtt bbTt bbtt

BBTT, BBTt, BbTT, BbTt = Black colour, trotting gait

BBtt, Bbtt - Black colour, pacing gait

bbTT, bbTt = chestnut colour, trotting gait

bbtt = chesnut colour, pacing gait