Question

there is a line that includes the point (11,5) and has a slope of 8/11. what is its equation in slope intercept form?

Answer 1

Explanation:

Slope-intercept form is y=mx+b where m is the slope and b is the y-intercept. We have all the information we need except for the y-intercept, so we can plug in our point to solve for the y-intercept.

------------------------------------Solving for y-intercept------------------------------------

Plugging in the point gives us
`5=8/11*11+b`. Simplifying this equation results in
`5=8+b`. To solve for b, we subtract 8 from both sides, giving us that
`b=-3`. We now have both the slope and the y-intercept, so our equation is y = 8/11x -3.

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Answer 2

`y=(8)/(11) x-3`

Explanation:

Plug in the slope and point into the equation y=mx+b to solve for the y-value of the y-intercept. Plug in the x value for x, the y value for y, and the slope for m.

`5=(8)/(11) (11)+b`

`5=8+b`

`-3=b`

After solving that, you can plug the slope and y-intercept back into the equation to solve for y.

`y=(8)/(11) x+(-3)`

`y=(8)/(11) x-3`