Question

Which of the relations given by the following sets of ordered pairs is a function?

O ((-2,5), (7, 5), (-4, 0), (3, 0), (1, — 6)}
O ((3, 3), (3, — 1), (3, 1), (3, 3), (3,5)}
O {(1, 2), (2, 3), (3, 4), (5, 6), (2, 1)}
O {(2,8), (1,-4), (0, 0), (1, 4), (2,8)}

Answer 1

Explanation:

be a function, there needs to be one unique

value of +y+ for every +x+

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The 1st set has 5 different values of +y+

for +x+=+1+ and violates definition

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The 2nd set is a function

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The 3rd set has

( 1,2 ) & ( 1,1 )

( 2,3 ) & ( 2,2 )

( 3,4 ) & ( 3,3 )

Each of these pairs violates the definition

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The 4th set has ( 2,-7 ) & ( 2,0 ) which

violate definition