Answer:
x^3y^2√xy
Explanation:
First, you calculate what's in the square root. x^2 becomes x and y^4 becomes y^2.
Then you distribute the 1/2 to the x^5 and the y so they become x^5/2 and y^1/2.
Next, you combine the like terms. x and x^5/2 becomes x^7/2. y^2 and y^1/2 become y^5/2.
So you have x^7/2 y^5/2
To get rid of the 2 on the bottom of the exponents you square root both variables.
So you get √x^7 y^5 (square rooted x^7 and y^5)
Simplify the square rooted problem to x^3 y^2 √xy
You get x to the third power y to the second power and square rooted xy.