Question

Calcium carbonate reacts with hydrochloric acid:

CaCO3 + 2HCl →→ CaCl2 + CO2 + H2O

Calculate the number of moles of
hydrochloric acid required to react exactly
with 5g of calcium carbonate.

Answer 1

0.1 mole

Step-by-step explanation:

According to the formula, 1 mol of CaCO3 will require 2 mol of HCl

Molar mass of CaCO3 = 40.08 + 12.01 + 3(16.00) = 100.09 g/mol

so the 5g of CaCO3 equals : 5g x (1 mol/100.09g) = 0.0499 or 0.05 mol

so the mole of HCl required is: 0.05 x 2 = 0.1 mol