Question

Which of the following equations has infinitely many real solutions?

A.
3(x-6)= 3x + 18
B.
3(x-6)= 3x - 18
C.
3x+1=x-1
3x + 1 = 3x - 1
D.

Answer 1

B: 3(x-6) = 3x-18

Explanation:

The left and right sides of this equation are actually equal! We can see this by dividing the 3 on the left through the parentheses. This gives us
`3x-18`, which is equal to the right-hand side of the equation!

To solidify this, we add 18 to both sides, and subtract 3x from both sides, which gives us that 0=0, so there are infinitely many solutions for x(since no matter what x is, it will result in 0=0 which is always true).

I hope this helps!