Question

Where does the line f(x) = x-1 cross the parabola g(x) = (x+2)^2-9?

Answer 1

The line and the parabola cross at x = -4 and x = 1

Explanation:

Set f(x) = g(x)

`x-1 = (x+2)^2-9\\x - 1 = x^2+4x+4-9\\x = x^2 + 4x - 4\\0 = x^2 + 3x - 4\\Factor\\0 = (x - 1) (x + 4)\\x = 1, -4`