Answer:
Lie #3
b^6 is not b^8
Explanation:
All the problems use the quotient rule of exponents, which says that you subtract the exponents when dividing by the same base.
If we plug in 2 for x on #3, we have
![(b^8)/(b^2)=b^(^8^-^2^)=b^6\\ b^6\\eq b^8](https://img.qammunity.org/2023/formulas/mathematics/high-school/b9bq58sby05glzkk5y93lbwf2opkps2nlt.png)
Furthermore, x would need to be 0 to make #3 true since 8-0 = 8