Register
Box measures 32 inches long, 6 inches wide and 8 inches high. What is the diagonal length of the box?
231k views
5 votes
Box measures 32 inches long, 6 inches wide and 8 inches high. What is the diagonal length

of the box?

User David Costa
by
7.9k points

1 Answer

5 votes

Answer:


2√(281) inches

Explanation:

Using the 3D Pythagorean theorem, the diagonal has length
√(32^2+6^2+8^2)=2√(281) inches.

User Thomas Kabassis
by
8.2k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.
Link Copied!