236,862 views
21 votes
21 votes
Solve the quadratic equation
y^2 −10y+21=0
y=?

User Peter Elliott
by
2.3k points

1 Answer

28 votes
28 votes

Answer: y = 3 or y=7

Explanation:


y^(2) -10y+21

what 2 factors of 21 can equal 10 when added together (1*21- no 3*7- yes)

Factor


(y-3)(y-7)

y-3=0

y=3

or y-7=0

y=7

User Dave Roma
by
3.0k points
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