Question

Consider the following inequality:

−2(2z−3)≥2z+24
Step 1 of 2 : Write the solution using interval notation.

Answer 1

z ∈ (-∞, -3]

Explanation:

You want the solution to −2(2z−3)≥2z+24.

Solution

Simplify the inequality:

-4z +6 ≥ 2z +24

-18 ≥ 6z . . . . . . . . . add 4z -24

-3 ≥ z . . . . . . . . divide by 6

The solution is z ∈ (-∞, -3].