Question

Use the given measurements to solve the triangle. Round lengths of sides to the nearest tenth and angle measures to the nearest degree.

a=400, b=300

Answer 1

`(\sin \theta)/(300)=(\sin 2\theta)/(400) \\ \\ (\sin \theta)/(300)=(2\sin \theta \cos \theta)/(400) \\ \\ (1)/(300)=(\cos \theta)/(200) \\ \\ \cos \theta=(2)/(3) \\ \\ \theta=\arccos(2/3) \\ \\ \theta \approx \boxed{48^(\circ)}`