Question

What is the rate constant of a reaction if rate = .2 (mol/L)s, [A] and [B] are each 3M, m=1 and n=2

Answer 1

Answer:
`7.407 * 10^(-3) \text{ M}^(-2) \text{ s}^(-1)`

Step-by-step explanation:

Note that rate is equal to
`k[A]^m [B]^n`, where
`k` is the rate constant,
`[A]` and
`[B]` are the concentrations,
`m` is the order of reactant A, and
`n` is the order of reactant B.

Substituting the given values,

`0.2=k(3^1)(3^2) \implies k=7.407 * 10^(-3) \text{ M}^(-2) \text{ s}^(-1)`