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Solve elimination method
3x+2y-15=0
5x-3y -25=0​

User Cui Heng
by
7.9k points

1 Answer

5 votes

Answer:

x=5

y=0

Explanation:

3x+2y−15=0

5x−3y−25=0

multiply the first equation by 3, and multiply the second equation by 2.

3(3x+2y−15=0)

2(5x−3y−25=0)

becomes:

9x+6y−45=0

10x−6y−50=0

add these equations to eliminate y:

19x−95=0

Then solve 19x−95=0 for x:

19x−95=0

19x−95+95=0+95 (add 95 to both sides)

19x=95

19x

19

=

95

19

(divide both sides by 19)

x=5

now that we've found x let's plug it back in to solve for y.

write down an original equation:

3x+2y−15=0

substitute 5for x in 3x+2y−15=0:

(3)(5)+2y−15=0

2y=0 (simplify both sides of the equation)

2y

2

=

0

2

(divide both sides by 2)

y=0

User Tzivia
by
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