Question

Find the number of grams in a 1.25 M solution of potassium nitrate (NO3) if we have

160 ml of the solution.

Answer 1

12.4 g

Step-by-step explanation:

M=1.25M

v=0.16L

molar mass = 62 g per mole

M=n/v

n=M*v

n=1.25M*0.16

• n=0.2mol
• n=mass of a substance /molar mass

mass of substance = n * M

m=0.2mole *62 g/mole

m=12.4g