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What volume of a 2.5 M NaCl solution must be diluted with water to produce 200. mL of a 0.10 M solution?​

User Duc
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Answer:one mole of NaCl weighs 58.44 g. A 2.5 M solution is 2.5 moles per liter (Molarity is just the number of moles per liter). Therefore, 0.5 L would contain 1.25 mol. Hence, you would need 1.25 × 58.44 g = 73 g.

Explanation:The formula for calculating a dilution is (C1) (V1) = (C2) (V2) where...

C1 is the concentration of the starting solution.

V1 is the volume of the starting solution.

C2 is the concentration of the final solution.

V2 is the volume of the final solution.

User Edgar Froes
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