Question

a capacitor is charged at a constant charging current of 2.0 x 10^-5A. The time taken to charge the capacitor is 30s and during this time the voltage across the capacitor rises from OV to 12V. What is the capacitance of the capacitor?​

Answer 1

5×10-5 farads

Step-by-step explanation:

Indications:

Q = charge

I = Current

t = Time

C = Capacitance

V = Voltage

Now, we know, Q = IT = 2×10^-5 ×30 = 6×10^-4 C

again, we know, Q = VC

⇒ C = Q/V = 6×10^-4/12 = 5×10^-5 Farads