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A waiter walks a distance of 5m holding a tray of food that weighs 10N. How much work has the waiter done on the tray?
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32 votes
32 votes
A waiter walks a distance of 5m holding a tray of food that weighs 10N. How much work has the waiter done on the tray?

User Serg Hospodarets
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2 Answers

21 votes
21 votes
Force(10N)xDistance(5m)=50j(work done)
User Silom
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19 votes
19 votes

Answer:

0 joule of workdone

Step-by-step explanation:


w = f * d * \cot( \beta )

force and the displacement are perpendicular to each other so cos(90⁰) =0

User Vibhav Singh Rohilla
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3.0k points
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