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39 votes
39 votes
To what temperature must a balloon, initially at 25°C and 2.00 L, be heated in order to have a volume of 6.00 L

User Reuelab
by
2.8k points

1 Answer

6 votes
6 votes

Answer:

894 deg K

Step-by-step explanation:

The computation is shown below:

Given that

V1 denotes the initial volume of gas = 2.00 L

T1 denotes the initial temperature of gas = 25 + 273 = 298 K

V2 denotes the final volume of gas = 6.00 L

T2 = ?

Based on the above information

Here we assume that the pressure is remain constant,

So,

V1 ÷ T1 = V2 ÷ T2

T2 = T1 × V2 ÷ V1

= (298)(6) ÷ (2)

= 894 deg K

User Milton
by
3.3k points