Following the pattern in (5)(3)+(2)(3) = (5+2)(3), we could do the same thing with 5x+2x = (5+2)x. We're basically un-distributing the common factor from each term.
And now with (5+2)x, we can add the 5 and 2 to get 7x.
If we substitute different values into 5x+2x, it works out to add up to 7 times that same substituted value. For example:
(5)(9)+(2)(9)=45+18=63
(7)(9)=63
If we substitute 9 into 7x-1, then we end up with 63-1 = 62.
In fact, any number we put into 5x+2x will always be one more than 7x-1. So, no, there doesn't seem to be any value of x that would make these equal. Since 5x+2x=7x, then 7x-1 will always be one less than 7x.