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Write the equation of the line passing through the points (-3,3) and (3,1).

The equation of the line is?

Write the equation of the line passing through the points (-3,3) and (3,1). The equation-example-1
User Kaay
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The equation is y=-1/3x+2
Write the equation of the line passing through the points (-3,3) and (3,1). The equation-example-1
User Snger
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Answer:

y = -1/3x + 2

Explanation:

Slope-intercept form of a linear equation is written as:

y = mx + b, where x and y are coordinates from one of the points on the line, m is the slope, and b is the y-intercept.

1. You'll first want to find the slope, m. Slope can be calculated from two points by using the equation (y1 - y2)/(x1 - x2). If you plug your two points into this equation for x and y (making sure that y1 and x1 are from the same point and y2 and x2 are from the other), you'll get,

(3 - 1)/(-3 - 3) = 2/-6 = -1/3

m = - 1/3

2. You can then plug your slope, m, into the slope-intercept form of the equation. Using one of your points (doesn't matter which, but I'll use (3,1)), you can solve for b, your y-intercept.

1 = -1/3(3) + b

1 = -1 + b

b = 2

3. Plug the variables into the equation.

For your final equation, plug the slope, m, and y-intercept, b, that you just found.

y = -1/3x + 2

User Userxxx
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