Question

What is the value of C in the matrix equation below?

|-18 3 51-c-[-22 1 12
o -40
217]
01-40 27]
10142-7)
0 14 2 17]

Answer 1

Answer: C

Step-by-step explanation: [ 4 2 -7 ]

Answer 2

Given:

The matrix equation is:

`\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}`

To find:

The value of matrix C.

Solution:

Let
`A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}`. Then the given equation can be rewritten as

`A-C=B`

`-C=B-A`

`C=-(B-A)`

`C=A-B`

On substituting the values of the matrices, we get

`C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}`

`C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}`

`C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}`

`C=\begin{bmatrix}-4&2&-7\end{bmatrix}`

Therefore, the correct option is C.