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The square root of (-2x)^2 for which values of x does the expression makes sense?

User Darron
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1 Answer

5 votes

Answer:
x\leq 0

Explanation:

The first thing we need to do is to make the argument or the number inside the square root equal or larger than zero:

-2x ≥ 0

x ≤ 0/-2

x ≤ 0

So the given expression only makes sense for x that is less than or equal to zero.

User H Bala
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3.6k points