Question

PAST DUE DATE NEED DONE NOW! NO LINKS! HELP ME FIND THE EQUATION

Answer 1

Equation: y=22x + 0 (you can put 0 if you want)

Explanation:

Okay, so this is set up as a y=mx+b equation meaning that m=rate of change and b=y-intercept. If a cheetah runs 22 feet per second which is x, that means that m=22. And if 1 second is equal to 22 feet then in 0 seconds they run 0 feet, which is your y-intercept. Another way to find the rate of change (m) is by using the equation y2-y1/x2-x1 or 44-22/1 in this case. This equation is usually written as y=22x. Hope this helps!

Answer 2

To write an equation for this line, you first need to understand how to derive it.

Let's utilize slope-intercept form, as it's the easiest to understand compared to any other form for line functions:

y = mx + b

m: The slope of the line

b: The y-intercept (The point where the line is at the y-axis)

Now that we've defined our variables, how do we go about making the actual equation? Let's start off with the slope, m.

The slope is a measure of how high or low the line is. The number is a ratio between the rise and run of a slope. In other words, it is essentially
`(rise)/(run)`

Let's look back at the graph. In the time interval from 1 to 2 seconds, we see that the line rises by 22 feet. Because the time interval is only 1 second, the run is 1 second.

Therefore:

m =
`(rise)/(run)`

m =
`(22)/(1)`

m = 22

We now have the first variable of the equation.

y = 22x + b

What about b? As we established earlier, b is the value of coordinate y at the y-intercept. Essentially, to find b we need to know what the value of y is when the coordinate x is 0.

As you can see from the graph you made, the value of y when x is 0 is also 0. This makes sense, too. How can the cheetah travel distance at 0 seconds when it obviously hasn't started moving? We now know b = 0. Now, we have gotten all of the variables we need to make a full equation:

y = 22x + 0

y = 22x

If you'd like me to explain how I did anything, just ask!

- breezyツ