Question

What is an equation of the line that passes through the point (-5,-3) and is parallel to the line 3x+5y=15

Answer 1

Answer:
`y+3=-(3)/(5)(x+5)`

Explanation:

The equation of the given line can be rearranged as follows:

`3x+5y=15\\\\5y=-3x+15\\\\y=-(3)/(5)x+3`

Parallel lines have the same slope, so the slope of the line we need to find is -3/5.

Substituting into point-slope form, the equation of the line is
`y+3=-(3)/(5)(x+5)`.