276,572 views
14 votes
14 votes
If the length of a rectangle is 12 times the width and the area is 48 square feet, what are the

dimensions?

User Nathan Noble
by
2.7k points

2 Answers

26 votes
26 votes

Answer:

Solution :-

Let the width be w and Length will be 12w

So,

Area = lw

48 = 12w × w

48/12 = w²

4 = w²

√4 = √w²

2 = 2

Length = 12(2) = 24 cm

Breadth = 2 cm


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User CloudWave
by
3.1k points
25 votes
25 votes

Answer:

dimensions are 2 ft, 24ft

Explanation:

width = w

length = 12w

Area of rectangle = 48 square feet

length * width = 48

12w * w = 48

12w² = 48 {Divide both side by 12}

w² = 48/12

w² = 4 =2²

w =2 ft

l = 12*2 = 24ft

User MatanRubin
by
3.1k points