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Supose 1.3 Kg of water are heated from 20 °C to 80 °C. How much energy was transferred to the

water?(Water Specific heat capacity is 4184 J/Kg-°C).

1 Answer

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Answer:

Q = (80 - 20) deg C * 1.3 kg * 4184 J / (deg C kg) = 326,000 Joules

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