Answer:
1. x = -9
2. a = 14
3. n =
![(2)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/zeht2hdwlb899wfchg7j67j4mj43o3xc1c.png)
Explanation:
Here are the steps to the first question:
1. Rearrange Terms
61 = 7 - 6x
61 = -6x + 7
2. Subtract 7 from both sides
61 = -6x + 7
61 - 7 = -6x + 7 - 7
3. Simplify
Subtract the numbers:
61 - 7 = -6x + 7 - 7
54 = -6x + 7 - 7
Subtract the numbers:
54 = -6x + 7 - 7
54 = -6x
4. Divide both sides by the same factor
54 = -6x
=
![(-6x)/(-6)](https://img.qammunity.org/2023/formulas/mathematics/college/sbe3nl9dtwz8jom73cwiyrgsrdqh8r9r2k.png)
5. Simplify
Divide the numbers:
=
![(-6x)/(-6)](https://img.qammunity.org/2023/formulas/mathematics/college/sbe3nl9dtwz8jom73cwiyrgsrdqh8r9r2k.png)
-9 =
![(-6x)/(-6)](https://img.qammunity.org/2023/formulas/mathematics/college/sbe3nl9dtwz8jom73cwiyrgsrdqh8r9r2k.png)
Cancel terms that are in both the numerator and denominator:
-9 =
![(-6x)/(-6)](https://img.qammunity.org/2023/formulas/mathematics/college/sbe3nl9dtwz8jom73cwiyrgsrdqh8r9r2k.png)
-9 = x
Move the variable to the left:
-9 = x
x = -9
Solution to Question 1:
x = -9
Here are the steps to the second question:
1. Combine multiplied terms into a single fraction
a - 26 = -5
- 26 = -5
2. Find common denominator
- 26 = -5
+
= -5
3. Combine fractions with common denominator
+
= -5
= -5
4. Multiply the numbers
= -5
= -5
5. Multiply all terms by the same value to eliminate fraction denominators
= -5
2 ·
= 2(-5)
6. Cancel multiplied terms that are in the denominator
2 ·
= 2(-5)
3a - 52 = 2(-5)
7. Multiply the numbers
3a - 52 = 2(-5)
3a - 52 = -10
8. Add 52 to both sides
3a - 52 = -10
3a - 52 + 52 = -10 + 52
9. Simplify
Add the numbers:
3a - 52 + 52 = -10 + 52
3a = -10 + 52
Add the numbers:
3a = -10 + 52
3a = 42
10. Divide both sides by the same factor
3a = 42
=
![(42)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/knq0wenn2m9qmknqbali1owwmlqmmpzwnb.png)
11. Simplify
Cancel terms that are in both the numerator and denominator:
=
![(42)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/knq0wenn2m9qmknqbali1owwmlqmmpzwnb.png)
a =
![(42)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/knq0wenn2m9qmknqbali1owwmlqmmpzwnb.png)
Divide the numbers:
a =
![(42)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/knq0wenn2m9qmknqbali1owwmlqmmpzwnb.png)
a = 14
Solution to Question 2:
a = 14
Here are the steps to the third question:
1. Divide the numbers
4 = n +
![(-10)/(-3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/9g4er641cf3f4mo213rlf78czxzgxud1km.png)
4 = n +
![(10)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/inmy3e8gctmqf3c20fmp9a4bvj6vjb2t8j.png)
2. Subtract
from both sides
4 = n +
![(10)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/inmy3e8gctmqf3c20fmp9a4bvj6vjb2t8j.png)
4 -
= n +
-
![(10)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/inmy3e8gctmqf3c20fmp9a4bvj6vjb2t8j.png)
3. Simplify
Subtract the numbers:
4 -
= n +
-
![(10)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/inmy3e8gctmqf3c20fmp9a4bvj6vjb2t8j.png)
= n +
-
![(10)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/inmy3e8gctmqf3c20fmp9a4bvj6vjb2t8j.png)
Subtract the numbers:
= n
Move the variable to the left:
= n
n =
![(2)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/zeht2hdwlb899wfchg7j67j4mj43o3xc1c.png)
Solution to Question 3:
n =
![(2)/(3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/zeht2hdwlb899wfchg7j67j4mj43o3xc1c.png)
I hope my answer helped you! If you need more information or help, comment down below and I will be sure to respond if I am online. Have a wonderful rest of your day!