164k views
3 votes
Will someone help me with this geometry please

Will someone help me with this geometry please-example-1
User Tomoyuki
by
4.4k points

2 Answers

2 votes
71.4

59/19 = 3.105263157894737

23 x 3.105263157894737 = 71.4 (rounded to nearest tenth)
User Martin Dandanell
by
4.4k points
3 votes

Answer:


\huge\boxed{\sf HF=71.4}

Explanation:

If ΔCDE is similar to ΔFGH, their sides are proportional.

So,


\displaystyle (23)/(HF) =(19)/(59) \\\\Cross \ Multiply\\\\23 * 59 = 19 * HF\\\\1357 = 29HF\\\\Divide \ 19 \ to \ both \ sides\\\\1357/19 = HF\\\\71.4 = HF\\\\HF=71.4\\\\\rule[225]{225}{2}